Python3 Snowflake算法实现不重复的分布式ID

  • Python3 Snowflake算法实现不重复的分布式ID
import time
 
# 64位ID的划分
WORKER_ID_BITS = 5
DATACENTER_ID_BITS = 5
SEQUENCE_BITS = 12
 
# 最大取值计算
MAX_WORKER_ID = -1 ^ (-1 << WORKER_ID_BITS) # 2**5-1 0b11111
MAX_DATACENTER_ID = -1 ^ (-1 << DATACENTER_ID_BITS)
 
# 移位偏移计算
WOKER_ID_SHIFT = SEQUENCE_BITS
DATACENTER_ID_SHIFT = SEQUENCE_BITS + WORKER_ID_BITS
TIMESTAMP_LEFT_SHIFT = SEQUENCE_BITS + WORKER_ID_BITS + DATACENTER_ID_BITS
 
# 序号循环掩码
SEQUENCE_MASK = -1 ^ (-1 << SEQUENCE_BITS)
 
# Twitter元年时间戳
TWEPOCH = 1288834974657
 
 
class InvalidSystemClock(Exception):
  """
  时钟回拨异常
  """
  pass
class IdWorker(object):
  """
  用于生成IDs
  """
 
  def __init__(self,datacenter_id=0, worker_id=0,did_wid=-1,  sequence=0):
    """
    初始化
    :param datacenter_id: 数据中心(机器区域)ID
    :param worker_id: 机器ID
    :param did_wid: 数据中心和机器ID合并成10位二进制,用十进制0-1023表示,通过算法会拆分成datacenter_id和worker_id
    :param sequence: 起始序号
    """
    if did_wid>0:
        datacenter_id = did_wid >> 5
        worker_id = did_wid ^ (datacenter_id << 5)
    # sanity check
    if worker_id > MAX_WORKER_ID or worker_id < 0:
      raise ValueError('worker_id值越界')
 
    if datacenter_id > MAX_DATACENTER_ID or datacenter_id < 0:
      raise ValueError('datacenter_id值越界')
 
    self.worker_id = worker_id
    self.datacenter_id = datacenter_id
    self.sequence = sequence
    self.last_timestamp = -1 # 上次计算的时间戳
 
  def _gen_timestamp(self):
    """
    生成整数时间戳
    :return:int timestamp
    """
    return int(time.time() * 1000)
 
  def get_ids(self, count):
      ids = []
      for i in range(count):
          ids.append(self.get_id())
      return ids
  def get_id(self):
    """
    获取新ID
    :return:
    """
    timestamp = self._gen_timestamp()
 
    # 时钟回拨
    if timestamp < self.last_timestamp:
      print('clock is moving backwards. Rejecting requests until {}'.format(self.last_timestamp))
      raise InvalidSystemClock
 
    if timestamp == self.last_timestamp:
      self.sequence = (self.sequence + 1) & SEQUENCE_MASK
      if self.sequence == 0:
        timestamp = self._til_next_millis(self.last_timestamp)
    else:
      self.sequence = 0
 
    self.last_timestamp = timestamp
 
    new_id = ((timestamp - TWEPOCH) << TIMESTAMP_LEFT_SHIFT) | (self.datacenter_id << DATACENTER_ID_SHIFT) | \
         (self.worker_id << WOKER_ID_SHIFT) | self.sequence
    return new_id
 
  def _til_next_millis(self, last_timestamp):
    """
    等到下一毫秒
    """
    timestamp = self._gen_timestamp()
    while timestamp <= last_timestamp:
      timestamp = self._gen_timestamp()
    return timestamp
 
if __name__ == '__main__':
    worker = IdWorker()
    index = 0
    while(index<100):
      print(worker.get_id())
      index = index +1

Python3 Snowflake算法实现不重复的分布式ID
https://www.gmtgo.com/32817.html
作者
大帅
发布于
2022年12月19日
许可协议