Python3 Snowflake算法实现不重复的分布式ID
- Python3 Snowflake算法实现不重复的分布式ID
import time
# 64位ID的划分
WORKER_ID_BITS = 5
DATACENTER_ID_BITS = 5
SEQUENCE_BITS = 12
# 最大取值计算
MAX_WORKER_ID = -1 ^ (-1 << WORKER_ID_BITS) # 2**5-1 0b11111
MAX_DATACENTER_ID = -1 ^ (-1 << DATACENTER_ID_BITS)
# 移位偏移计算
WOKER_ID_SHIFT = SEQUENCE_BITS
DATACENTER_ID_SHIFT = SEQUENCE_BITS + WORKER_ID_BITS
TIMESTAMP_LEFT_SHIFT = SEQUENCE_BITS + WORKER_ID_BITS + DATACENTER_ID_BITS
# 序号循环掩码
SEQUENCE_MASK = -1 ^ (-1 << SEQUENCE_BITS)
# Twitter元年时间戳
TWEPOCH = 1288834974657
class InvalidSystemClock(Exception):
"""
时钟回拨异常
"""
pass
class IdWorker(object):
"""
用于生成IDs
"""
def __init__(self,datacenter_id=0, worker_id=0,did_wid=-1, sequence=0):
"""
初始化
:param datacenter_id: 数据中心(机器区域)ID
:param worker_id: 机器ID
:param did_wid: 数据中心和机器ID合并成10位二进制,用十进制0-1023表示,通过算法会拆分成datacenter_id和worker_id
:param sequence: 起始序号
"""
if did_wid>0:
datacenter_id = did_wid >> 5
worker_id = did_wid ^ (datacenter_id << 5)
# sanity check
if worker_id > MAX_WORKER_ID or worker_id < 0:
raise ValueError('worker_id值越界')
if datacenter_id > MAX_DATACENTER_ID or datacenter_id < 0:
raise ValueError('datacenter_id值越界')
self.worker_id = worker_id
self.datacenter_id = datacenter_id
self.sequence = sequence
self.last_timestamp = -1 # 上次计算的时间戳
def _gen_timestamp(self):
"""
生成整数时间戳
:return:int timestamp
"""
return int(time.time() * 1000)
def get_ids(self, count):
ids = []
for i in range(count):
ids.append(self.get_id())
return ids
def get_id(self):
"""
获取新ID
:return:
"""
timestamp = self._gen_timestamp()
# 时钟回拨
if timestamp < self.last_timestamp:
print('clock is moving backwards. Rejecting requests until {}'.format(self.last_timestamp))
raise InvalidSystemClock
if timestamp == self.last_timestamp:
self.sequence = (self.sequence + 1) & SEQUENCE_MASK
if self.sequence == 0:
timestamp = self._til_next_millis(self.last_timestamp)
else:
self.sequence = 0
self.last_timestamp = timestamp
new_id = ((timestamp - TWEPOCH) << TIMESTAMP_LEFT_SHIFT) | (self.datacenter_id << DATACENTER_ID_SHIFT) | \
(self.worker_id << WOKER_ID_SHIFT) | self.sequence
return new_id
def _til_next_millis(self, last_timestamp):
"""
等到下一毫秒
"""
timestamp = self._gen_timestamp()
while timestamp <= last_timestamp:
timestamp = self._gen_timestamp()
return timestamp
if __name__ == '__main__':
worker = IdWorker()
index = 0
while(index<100):
print(worker.get_id())
index = index +1
Python3 Snowflake算法实现不重复的分布式ID
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